MrMeans
Well-Known Member
So I have decided that I want to do an experiment. I want to do a few single hop ipa's but for the different hop varieties I want to familiarize myself with I know I do not have the time now the capacity to brew a 5 gallon batch of each. Instead my plan is to start off with a pretty neutral grain bill. Some 2 row, maybe a little crystal 40, and possibly some carapils. Mash that and attempt to collect roughly 7.5 gallons of wort. I will then take this 7.5 gallons, split it into 5 equal parts, and do five separate boils. I will follow the same hop schedule and dosing on each boil. My question to the HBT community is this: WHen I boil with a full size batch I generally lose roughly a 1 gallon an hour. It is my understanding that this is fairly common normal hence why you generally pull 6-6.5 galls of wort when you mash out. A main factor of the boil off rate is the surface area of the boiling wort. I plan to do my boils in some smaller pots thus decreasing my surface area and my boil off rate. Does anyone have a good formula or rule of thumb that they use to calculate the boil off rate? Does anyone have any tips on things to watch out for doing smaller boils? Am I just wasting my time and should just scale down to 2.5 gallon batches instead of ~1.25?