CorgiBrew
Well-Known Member
Okay, this is for all of you EE's out there. I posted a couple of days ago about a wiring variation I'm considering for my panel based on Kal's design. To summarize, instead of powering the element indicator lights off of Hot A&B (downstream of a contactor between the power source and the heating element), I'm thinking of just using Hot A and the nuetral bus. Someone commented in response that I should use a diode to prevent current backflow throught the LED, presumably energizing the heating element circuit even when the contactor is "off". Sounds reasonable, but I have a couple of questions:
The LED indicator lamp has a circuit made up of a diode and a resistor. The resistor, I assume, drops the current to a manageable (<20 ma) level for the diode. The diode itself should prevent backflow from the neutral bus. So, do I really need another diode in the line? If there were backflow, wouldn't it be at a very low (reasonably "safe") level because of the resistor?
Since I'm unsure, I will likely take the easy route and just put the indicator lamp in line with the selector switch. Or do what Kal did and power the lamp with both hot leads, though I'd rather keep 220V off of the front of my panel. I'd still, from a learning perspective, be interested in any answers to the above.
The LED indicator lamp has a circuit made up of a diode and a resistor. The resistor, I assume, drops the current to a manageable (<20 ma) level for the diode. The diode itself should prevent backflow from the neutral bus. So, do I really need another diode in the line? If there were backflow, wouldn't it be at a very low (reasonably "safe") level because of the resistor?
Since I'm unsure, I will likely take the easy route and just put the indicator lamp in line with the selector switch. Or do what Kal did and power the lamp with both hot leads, though I'd rather keep 220V off of the front of my panel. I'd still, from a learning perspective, be interested in any answers to the above.