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DrBrewDC

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here is a question I have not seen asked nor answered in this forum, yet (of course, it may be out there and I have just not come across it)...

If my OG was 1.078 (which it was) and my FG is 1.020 (and it is) and therefore, the ABV calculates to a glorious 7.73% (which I must presume) and I add precisely 10ozs of 40% alc/vol bourbon to approximately 5 (but probably a bit more), how would I go about predicting the final ABV?
 
My fuzzy math and fuzzy logic seems to say that it will add approximately .625% to your final ABV... but I've been wrong before.
 
5gal * 7.73% + 10 fl oz * 40% = .3865 gallons + 4 oz = .41775 gallons.

.41775 gal / 5 gal (rounding down) = 0.08355 = Roughly 8.35%.
 
So 7.73 + .625 = 8.335 therefore (8.335 + 8.22 + 8.35) / 3 = 8.30 ABV

(my math skills are great enough to be able to calculate the mean). :eek:

Thank y'all!!
 
8.25% vs 8.3%? If you can taste (or feel) a difference you are a better man than I. At least OP has a ballpark for reference... i.e. don't pretend it's BMC and chug 4 really quick.
 
I agree with wierdboy:
In beer: 7.73%*640 oz = 49.472 oz of alcohol
Addition:40%*10 oz = 4 oz alcohol
Total alcohol: 53.472 oz

New volume: 640+10 = 650 oz

New ABV: 53.472/650 = 8.22%
 
Roughly 8.2261538% or so, give or take a bit here or there, approximately.
 
Where the heck does that 4oz come from?

4oz of alcohol, which is 40% of 10 oz.

It is not 8.3% it is 8.22%

You have to account for the additional volume you add with the bourbon.

Yes, assuming infinite precision. But he stated his volume is "approximately 5 (but probably a bit more)". So we're talking maybe +/- a quart or two. So to account for a range of most likely results, you could give him a margin of error if you wanted to get really technical.

But since his total volume is an approximation anyway, 8.3% and 8.22% are both approximations and both probably in the right ballpark. I could have accounted for the additional 10oz of bourbon, but that's 1.6% of his stated initial volume, which given the precision of his measurement is somewhat negligible to the actual result, since it's not going to be accurate to a tenth of a percentage point anyway.
 
So to clarify, let's assume his beer is somewhere between 4.75 and 5.5 gallons.

Then the initial range of volume of alcohol is given by:

7.73% * [608..704] = [47..54].

He then adds 4 oz (40% of 10 oz) with the bourbon, giving him a total alcohol volume range of:

[51..58]

Dividing back into the total volume:

[58 / 714..51 / 618] = [8.12%..8.25%]

Ah. Well, I take my crow grilled medium well and lightly seasoned then.
 
So to clarify, let's assume his beer is somewhere between 4.75 and 5.5 gallons.

Then the initial range of volume of alcohol is given by:

7.73% * [608..704] = [47..54].

He then adds 4 oz (40% of 10 oz) with the bourbon, giving him a total alcohol volume range of:

[51..58]

Dividing back into the total volume:

[58 / 714..51] = [8.12%..8.25%]

Ah. Well, I take my crow grilled medium well and lightly seasoned then.

I enjoyed the entire debate. The best part? A man able to admit when he is wrong; a rarity these days. Kudos to you, bernerbrau! :mug:
 
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