brad2157
Well-Known Member
I'm looking to go electric and possibly picking up a 20l Speidel Braumeister. I'm currently renting a house and do not have a 220V plug available in the garage (or a free open one in the house either). I only have a few 120V outlets in the garage. I'm 99.9% sure I wouldn't be allowed to add a 220V circuit to the garage, nor do I really want to spend the money doing so, knowing I'll be moving out in a year or so. Saw an old post some time back from where someone was selling a BM that came with a 110V > 200V step up transformer to power it. I'm assuming this is a safe device to use and would work nicely in my situation, but here is what I came up with below.
I know that typically the power measurements are posted/listed as "peak power" and not constant/RMS power output for inverters/transformers. I know to power the BM 20l, you would need something that would put out at least 2,023 watts constant (2,000 watts for the heating element and 23 watts for the pump). The specs listed for the BM are 220-230V with at least 10amp protection.
If I were to purchase one of these 5,000 watt transformer units, would this work to safely power the BM? From the power calculations, I think I should be fine power wise.
https://www.amazon.com/dp/B008GQTXS0/?tag=skimlinks_replacement-20
5,000 watts peak = 3,535 watts continuous (RMS Power)
RMS power = Peak Power x 0.707
Has anyone tried this before?
I know that typically the power measurements are posted/listed as "peak power" and not constant/RMS power output for inverters/transformers. I know to power the BM 20l, you would need something that would put out at least 2,023 watts constant (2,000 watts for the heating element and 23 watts for the pump). The specs listed for the BM are 220-230V with at least 10amp protection.
If I were to purchase one of these 5,000 watt transformer units, would this work to safely power the BM? From the power calculations, I think I should be fine power wise.
https://www.amazon.com/dp/B008GQTXS0/?tag=skimlinks_replacement-20
5,000 watts peak = 3,535 watts continuous (RMS Power)
RMS power = Peak Power x 0.707
Has anyone tried this before?
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