CyberFox
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- Joined
- Mar 29, 2022
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I was thinking about doing no sparge for a 5 gallon batch. I'm trying to figure out the max amount of grains that can fit in a 12 gallon mash tun (cooler). Here's an example using numbers I came up with in Beersmith:
Grain amount: 35 lbs.
Grain absorption: 2.56 gallons
Pre-boil volume: 6.69 gallons
Total mash water volume: 9.25 gallons
Mash volume needed: 11.99 gallons
I feel like I'm missing something and I'm sure it's something obvious. If anyone could help me out, I'd really appreciate it!
Grain amount: 35 lbs.
Grain absorption: 2.56 gallons
Pre-boil volume: 6.69 gallons
Total mash water volume: 9.25 gallons
Mash volume needed: 11.99 gallons
I feel like I'm missing something and I'm sure it's something obvious. If anyone could help me out, I'd really appreciate it!