Hello,
I am going to do a partial mash dogfish 60 clone.
My grain bill is about 7.5lbs plus 5lbs of LME.
I am aware of the golden 1.25qt to lb rule and I have BS 2.1 but I am a really new brewer and not quite sure about my quantities.
BS wants me to do something like 10 gallons of total water... and the golden rule would put me little under that...
However, I was planning on steeping in my BK for 30 minutes and then stirring in the LME and bringing to a boil. Essentially my "sparge" would be me drawing off from the bottom of my kettle and pouring that over my grain bags before adding the LME.
If I am going to do it this way it seems like I would want my entire volume in my initial steep, which intuitively I would guess would be closer to 8 gallons (1 gallon of grain absorption and 1+ gallon boil off) in order to bring me to 5.5 gallons which will give me a 5 gallon kegging volume.
Can someone explain how much water they would use in this situation and why?
Thanks very much!
I am going to do a partial mash dogfish 60 clone.
My grain bill is about 7.5lbs plus 5lbs of LME.
I am aware of the golden 1.25qt to lb rule and I have BS 2.1 but I am a really new brewer and not quite sure about my quantities.
BS wants me to do something like 10 gallons of total water... and the golden rule would put me little under that...
However, I was planning on steeping in my BK for 30 minutes and then stirring in the LME and bringing to a boil. Essentially my "sparge" would be me drawing off from the bottom of my kettle and pouring that over my grain bags before adding the LME.
If I am going to do it this way it seems like I would want my entire volume in my initial steep, which intuitively I would guess would be closer to 8 gallons (1 gallon of grain absorption and 1+ gallon boil off) in order to bring me to 5.5 gallons which will give me a 5 gallon kegging volume.
Can someone explain how much water they would use in this situation and why?
Thanks very much!